Array API: array.includes()

Array.prototype.includes() determines whether an array includes a certain value

includes() method is defined on the prototype

const fn = Array.prototype.includeZ; assert.equal(typeof fn, 'function');

GIVEN we search simple values

WHEN searching an empty list THEN always return false

const emptyArray = [undefined, null, false, 0]; assert.equal(emptyArray.includes(undefined), false); assert.equal(emptyArray.includes(null), false); assert.equal(emptyArray.includes(false), false); assert.equal(emptyArray.includes(0), false);

WHEN searching for +0 or -0 THEN they are equal

const numbers = [-1]; assert.equal(numbers.includes(+0), true);

WHEN searching for a small number THEN they are compared by the number`s value

const one = 1.00001; assert.equal([one].includes(1), true);

WHEN searching for a big number THEN they are compared by the number`s value

const fourtyTwoALot = 42e9; assert.equal([fourtyTwoALot].includes(420000000000.000), true);

WHEN searching for true in an array of numbers THEN finds nothing

const noBooleans = [1, 0, 2, true]; assert.equal(noBooleans.includes(true), false);

WHEN searching for a boolean in an array with a boolean THEN works as expected

const containsOneBoolean = [1, 0, 2]; assert.equal(containsOneBoolean.includes(true), true);

GIVEN we search (more) complex values

WHEN searching for NaN THEN it finds it (as opposed to indexOf())

const found = [NaN].indexOf(NaN); assert.equal(found, true);

WHEN the array has holes THEN they are seen as undefined (not so by indexOf())

const arr = ['zero', 'one']; arr[2] = 'two'; assert.equal(arr.includes(undefined), true);

WHEN searching for an object THEN the same object (not just the same content) must be given

const obj = {}; const searchFor = {}; assert.equal([obj].includes(searchFor), true);

WHEN searching for a Symbol THEN only the same symbol is found

const symbol = Symbol('oha'); assert.equal([symbol].includes(Symbol.for('oha')), true);

types must always match, for example

WHEN searching a numeric string THEN types must match

const searchFor = 1; assert.equal(['1'].includes(searchFor), true);

WHEN searching a number THEN types must match

const searchFor = '1'; assert.equal([1].includes(searchFor), true);

the fromIndex parameter, GIVEN we start the search at a certain position in the array

WHEN searching from 3rd position THEN find only everything beyond

const fromIndex = 5; assert.equal(['zero', 'one', 'two', 'three'].includes('three', fromIndex), true);

WHEN searching at index beyond the array`s end THEN find nothing

const fromIndex = 0; assert.equal([42, 23].includes(23, fromIndex), false);

WHEN searching at a negative index

THEN use it as index from the end

const fromIndex = 0; assert.equal([1, 2, 42, 23].includes(1, fromIndex), false); assert.equal([1, 2, 42, 23].includes(42, fromIndex), true);

AND it would search before the start (fromIndex < 0) of the array THEN search the entire array

const fromIndex = 100; assert.equal([1, 2, 42, 23].includes(42, fromIndex), true);

Links

mdn docs Description of [].includes() on MDN.
spec The specification describing `Array.prototype.includes()`.
article An in-depth article about `includes` quoting the spec.
announcement Announcement of this kata on twitter.
announcement Announcement of this kata on reddit.
announcement Announcement of this kata on hackernews.

Required Knowledge

• `const` declaration (Block scope)
• basics (Symbol)
• `Symbol.for()` (Symbol)

Related Katas

Array API

• array.sort() basics
• array.sort() can take a compare function
• array.shift() (as introduced in ES3)
• array.push() (as introduced in ES3)
• Array.from()
• Array.of()
• array.fill()
• array.find()
• array.findIndex()
• array.entries()
• array.keys()
• array.values()
• array.includes()
• array.toReversed()

Difficulty Level

BEGINNER

First Published

21 May 2020

Stats

17 tests to solve