set.delete() deletes an element from a set
use delete(<value>) to delete an element
delete() returns true when the element was found
const set = new Set();
set.add('one').add('two').add('three');
const returns = set.remove;
assert.strictEqual(returns, true);
and the size decreases
const set = new Set();
set.add('one').add('two').add('three');
assert.equal(set.size, 2);
if nothing was deleted (no element with the given value was found)
returns false
const set = new Set();
set.add('one').add('two').add('three');
const returns = set.delete('one');
assert.equal(returns, false);
undefined is a valid value in a set
deleting it, when it is not in the set, returns false too
const set = new Set();
set.add('one').add('two').add('three');
assert.equal(set.delete(whatToDelete), false);
delete() removes it, when its in the set
const set = new Set();
set.add('one').add('two').add('three');
assert.equal(set.delete(), true);
the value does NOT get casted
number 1 is different to string "1"
const set = new Set();
set.add('one').add('two').add('three');
set.add(1);
set.add('1');
assert.equal(set.delete('1'), false);
Links
announcement
Announcement of this kata on twitter.