Set: set.delete()

set.delete() deletes an element from a set

use delete(<value>) to delete an element

delete() returns true when the element was found

const set = new Set(); set.add('one').add('two').add('three'); const returns = set.remove; assert.strictEqual(returns, true);

and the size decreases

const set = new Set(); set.add('one').add('two').add('three'); assert.equal(set.size, 2);

if nothing was deleted (no element with the given value was found)

returns false

const set = new Set(); set.add('one').add('two').add('three'); const returns = set.delete('one'); assert.equal(returns, false);

undefined is a valid value in a set

deleting it, when it is not in the set, returns false too

const set = new Set(); set.add('one').add('two').add('three'); assert.equal(set.delete(whatToDelete), false);

delete() removes it, when its in the set

const set = new Set(); set.add('one').add('two').add('three'); assert.equal(set.delete(), true);

the value does NOT get casted

number 1 is different to string "1"

const set = new Set(); set.add('one').add('two').add('three'); set.add(1); set.add('1'); assert.equal(set.delete('1'), false);

Links

announcement Announcement of this kata on twitter.

Required Knowledge

• `let` declaration (Block scope)
• `const` declaration (Block scope)
• basics (Set)
• `set.add()` (Set)

Related Katas

Set

• basics
• set.add()
• set.delete()
• the API
• set.clear()

Difficulty Level

BEGINNER

First Published

15 July 2015

Stats

6 tests to solve